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Python > Learn Python > How to remove matching elements from two nested lists...
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How to remove matching elements from two nested lists while iterating

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for i in list_1: for j in list_2: if i==j: list_1.remove(i) list_2.remove(j)
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IT Teacher

a= b= for i in a: if a in b: a.remove(i) b.remove(i)
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for set in dataSet: for item in set: if item=="311472": dataSet.remove(item)
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Train the students to shine in IT world.

Try with this: 1. Instead of deleting an element from the loop I would suggest you to try with the While loop. 2. Once when the iteration completed then delete the item lists which you would like to delete from the item list.
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IT Teacher

Here is the code to do a= b= for i in a: if i in b: a.remove(i) b.remove(i) print("a:%s,b:%s",%(a,b))
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Trainer

You can use list iterators, and can delete the elements while traversing the list.
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l=,] flag = 0 for x in l: if (flag == 0): list1=x flag = 1 else: list2=x if : print("Number was found") list1.remove(item) list2.remove(item) else: print("Number not in list")
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IT Professional Trainer with 15 years of experience in IT Industry

You could always iterate over a copy of the list, leaving you free to modify the original: for item in list(somelist): ... somelist.remove(item)
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Expert Php Developer and Php Programing Teacher

in nested loop check if value is equal to parent while loop
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Trainer

First unpack the nested list(L) into two separate lists (L1, L2). Then create a new list LC which contains common elements from L1 and L2. Iterate through LC, for each element 'elem', use L.remove(elem) and L.remove(elem)... Then display L. You will not see the matching elements in the two nested lis...
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First unpack the nested list(L) into two separate lists (L1, L2). Then create a new list LC which contains common elements from L1 and L2. Iterate through LC, for each element 'elem', use L[0].remove(elem) and L[1].remove(elem)... Then display L. You will not see the matching elements in the two nested lists.... read less
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