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Answered on 05 Mar Learn Lines and Angles

Sadika

If the complement of an angle is 28°, then the complement of the angle and the angle itself add up to 90°. Let the angle be x degrees. So, we have:x + 28 = 90 Now, let's solve for x: x = 90 - 28x = 62 Now, we know that the supplement of an angle is the amount by which the angle needs to be increased... read more

If the complement of an angle is 28°, then the complement of the angle and the angle itself add up to 90°.

Let the angle be x degrees.

So, we have:
x + 28 = 90

Now, let's solve for x:

x = 90 - 28
x = 62

Now, we know that the supplement of an angle is the amount by which the angle needs to be increased to reach 180°.

So, the supplement of the angle is:
180 - x

Substituting the value of x, we get:

180 - 62 = 118

Therefore, the supplement of the angle is 118°.

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Answered on 05 Mar Learn Practical Geometry

Sadika

1. Draw three non-collinear points A, B, and C.2. Connect these points to form triangle ABC.3. Draw a line through vertex A parallel to side BC. Let's call this line a'.4. Draw a line through vertex B parallel to side AC. Let's call this line b'.5. Draw a line through vertex C parallel to side AB. Let's... read more

1. Draw three non-collinear points A, B, and C.
2. Connect these points to form triangle ABC.
3. Draw a line through vertex A parallel to side BC. Let's call this line a'.
4. Draw a line through vertex B parallel to side AC. Let's call this line b'.
5. Draw a line through vertex C parallel to side AB. Let's call this line c'.

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Answered on 05 Mar Learn Practical Geometry

Sadika

To draw triangle ABC with side lengths AB = 5.5 cm, BC = 6 cm, and CA = 7 cm, as well as the perpendicular bisector of side BC, follow these steps: Draw a line segment of length 6 cm. This will represent side BC. At one end of the line segment, mark point B. With B as the center and a radius... read more

To draw triangle ABC with side lengths AB = 5.5 cm, BC = 6 cm, and CA = 7 cm, as well as the perpendicular bisector of side BC, follow these steps:

  1. Draw a line segment of length 6 cm. This will represent side BC.
  2. At one end of the line segment, mark point B.
  3. With B as the center and a radius of 5.5 cm, draw an arc to intersect the line segment BC. Mark this point as A.
  4. Measure a distance of 7 cm from point A along the line segment BA. Mark this point as C.
  5. Connect points A, B, and C to form triangle ABC.
  6. Now, find the midpoint of side BC. This midpoint will be the point where the perpendicular bisector intersects side BC.
  7. Draw a perpendicular line to side BC passing through the midpoint of BC. This line is the perpendicular bisector of side BC.

The triangle ABC is now drawn with side lengths AB = 5.5 cm, BC = 6 cm, and CA = 7 cm, and the perpendicular bisector of side BC is also drawn.

 
 
 
 
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Answered on 05 Mar Learn Practical Geometry

Sadika

Area of a rectangular field with sides 200 m and 125 m: Given: Length = 200 m, Width = 125 mArea = length * widthArea = 200 m * 125 mArea = 25,000 square meters
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Answered on 07 Mar Learn Symmetry

Sadika

For an isosceles triangle, the line of symmetry can also be referred to as the "axis of symmetry." This line divides the triangle into two mirror-image parts, running from the apex (the vertex opposite the base) to the midpoint of the base. read more

For an isosceles triangle, the line of symmetry can also be referred to as the "axis of symmetry." This line divides the triangle into two mirror-image parts, running from the apex (the vertex opposite the base) to the midpoint of the base.

 
 
 
 
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Answered on 07 Mar Learn Symmetry

Sadika

Shapes with no line of symmetry do not divide into two mirror-image halves, regardless of how you try to fold or bisect them. Here are three examples: Scalene Triangle: A triangle with all sides of different lengths and all angles of different sizes has no line of symmetry because there... read more

Shapes with no line of symmetry do not divide into two mirror-image halves, regardless of how you try to fold or bisect them. Here are three examples:

  1. Scalene Triangle: A triangle with all sides of different lengths and all angles of different sizes has no line of symmetry because there is no way to divide it into two parts that are mirror images of each other.

  2. Irregular Polygon: An irregular polygon, which does not have equal-length sides or equal angles, typically has no line of symmetry. An example would be a five-sided polygon where no two sides or angles are the same.

  3. Parallelogram (excluding rectangles and rhombuses): A general parallelogram (which is not a rectangle or rhombus) has no lines of symmetry. Its opposite sides are equal in length, and opposite angles are equal, but it does not fold into two parts that are mirror images of each other unless it is a special type like a rectangle or rhombus, which do have lines of symmetry.

These shapes illustrate that symmetry is not a universal characteristic of all geometric figures.

 
 
 
 
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Answered on 07 Mar Learn Perimeter and Area

Sadika

To find the area of a square with a side length of 16.5 decameters (dam) in square meters: Area = side^2 = (16.5 dam)^2 = 16.5^2 dam^2 = 272.25 m^2 So, the area of the square is 272.25 square meters. read more

To find the area of a square with a side length of 16.5 decameters (dam) in square meters:

Area = side^2 = (16.5 dam)^2 = 16.5^2 dam^2 = 272.25 m^2

So, the area of the square is 272.25 square meters.

 
 
 
 
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Answered on 07 Mar Learn Perimeter and Area

Sadika

To find the area of a rectangular field in acres with sides of 200 meters and 125 meters: Then, we convert the area from square meters to acres. Since 1 acre is equal to 4046.86 square meters: So, the area of the rectangular field is approximately 6.18 acres. read more

To find the area of a rectangular field in acres with sides of 200 meters and 125 meters:

Then, we convert the area from square meters to acres. Since 1 acre is equal to 4046.86 square meters:

So, the area of the rectangular field is approximately 6.18 acres.

 
 
 
 
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Answered on 07 Mar Learn Perimeter and Area

Sadika

To find the cost of painting the wall, we first need to calculate the area of the wall excluding the area covered by the door, and then multiply it by the cost per square meter. Calculate the cost: Cost per square meter = Rs 2.50Total cost = Area of the wall excluding the door × Cost per square... read more

To find the cost of painting the wall, we first need to calculate the area of the wall excluding the area covered by the door, and then multiply it by the cost per square meter.

Calculate the cost:

  • Cost per square meter = Rs 2.50
    Total cost = Area of the wall excluding the door × Cost per square meter

    So, the cost of painting the wall is Rs 235.

     
     
     
     
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Answered on 07 Mar Learn Perimeter and Area

Sadika

First, let's find the distance around the field, which is the perimeter of the rectangle: Perimeter of the rectangle = 2 × (Length + Width) = 2 × (290 m + 210 m) = 2 × 500 m = 1000 m Now, let's find the time it takes for the girl to go two times around the field: Distance... read more

First, let's find the distance around the field, which is the perimeter of the rectangle:

Perimeter of the rectangle = 2 × (Length + Width) = 2 × (290 m + 210 m) = 2 × 500 m = 1000 m

Now, let's find the time it takes for the girl to go two times around the field:

Distance covered = 2 × Perimeter of the field = 2 × 1000 m = 2000 m

Given that the girl walks at the rate of 1.5 m/sec, we can use the formula:

Time = Distance / Speed

Time = 2000 m / 1.5 m/sec ≈ 1333.33 sec

So, it will take approximately 1333.33 seconds for the girl to go two times around the field.

 
 
 
 
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