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To find the multiples of a number, you multiply that number by integers. Let's find the first three multiples of 11:

1. 11×1=1111×1=11
2. 11×2=2211×2=22
3. 11×3=3311×3=33

So, the first three multiples of 11 are 11, 22, and 33.

1. Gather Materials: You'll need a ruler and a blank sheet of paper.

2. Mark Starting Point: Place the ruler horizontally on the paper. Use a pencil to make a small mark at the starting point of the line segment.

3. Measure and Mark Length: Starting from the mark you made, use the ruler to measure 7.3 cm along the paper. Make another small mark at this point.

4. Draw Line: Connect the two marks using a straight line drawn with your pencil. Ensure that your line is straight and extends from the starting point to the end point.

5. Check Length: Measure the line segment you've drawn using the ruler to verify that it is indeed 7.3 cm long.

By following these steps carefully, you can draw a line segment of length 7.3 cm accurately using a ruler and a pencil.

To construct a line segment of length 5.6 cm using a ruler and compasses, follow these steps:

1. Gather Materials: You'll need a ruler, compass, pencil, and a blank sheet of paper.

2. Draw a Straight Line: Use the ruler and pencil to draw a straight line. This will serve as the base for your construction.

3. Mark the Starting Point: Choose a point on the line to serve as the starting point of your line segment. Label it as point A.

4. Draw an Arc: With the compass, draw an arc above the line segment from point A. Adjust the compass width to approximately 5.6 cm (or slightly longer for accuracy).

5. Draw Another Arc: Without changing the compass width, draw another arc below the line segment from point A. Ensure that the arcs intersect the line.

6. Connect Intersection Points: Use the ruler and pencil to draw a straight line connecting the two intersection points on the line. This line segment will be 5.6 cm in length.

7. Label the Endpoint: Label the endpoint of the line segment as point B.

Now, you have constructed a line segment AB with a length of 5.6 cm using a ruler and compasses.

To compare the given numbers:

1. 7
2. 12
3. 540
4. 71,25,400

We'll start by comparing the numbers at the highest place value, and if necessary, move on to the next highest place value until a clear winner is determined.

Looking at the numbers:

• 7 is the smallest.
• 12 is greater than 7.
• 540 is greater than 12.
• 71,25,400 is greater than 540.

So, the greatest number among the given numbers is 71,25,400.

To find out by how much it is greater than the next greatest number, we'll subtract the next greatest number (540) from the greatest number (71,25,400):

71,25,400−540=71,24,86071,25,400−540=71,24,860

So, 71,25,400 is greater than 540 by 71,24,860.

To form the smallest and greatest 5-digit numbers using the digits 0, 2, 4, 6, 8 without repetition, we arrange the digits in ascending and descending order respectively.

Smallest 5-digit number:

1. Place the smallest digit, which is 0, in the leftmost position.
2. Arrange the remaining digits, 2, 4, 6, 8, in ascending order from left to right.

So, the smallest 5-digit number using the digits 0, 2, 4, 6, 8 without repetition is 20,468.

Greatest 5-digit number:

1. Place the greatest digit, which is 8, in the leftmost position.
2. Arrange the remaining digits, 6, 4, 2, 0, in descending order from left to right.

So, the greatest 5-digit number using the digits 0, 2, 4, 6, 8 without repetition is 86,420.

Given: Number of packets: 39 Number of pens per packet: 12 Cost of 39 packets of 12 pens each: ₹374.40

To find: Cost of 52 packets of 10 pens each

Let's first find the cost per pen:

Cost of 39 packets of 12 pens = ₹374.40

Cost per pen = Total cost ÷ Total number of pens Cost per pen = ₹374.40 ÷ (39 * 12) Cost per pen = ₹374.40 ÷ 468 Cost per pen = ₹0.80

Now, let's find the cost of 52 packets of 10 pens each:

Number of packets: 52 Number of pens per packet: 10

Total number of pens = 52 * 10 = 520 pens

Total cost = Cost per pen × Total number of pens Total cost = ₹0.80 × 520 Total cost = ₹416

Therefore, the cost of 52 packets of 10 pens each is ₹416.

Through one given point, infinitely many lines can be drawn. This is because any straight line can pass through a single point. So, for any point, there are infinite lines that can be drawn through it.

A kite has one line of symmetry.

A kite is a quadrilateral with two distinct pairs of adjacent sides that are congruent. It has one line of symmetry passing through the intersection of its diagonals, which divides it into two congruent halves. Therefore, a kite has one line of symmetry