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Out of 12 consonants and 4 vowels, how many words of 6 consonants and 3 vowels can be formed?

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Number of ways to select 6 consonants from 12 = 12C6 Number of ways to select 3 vowels from 4 = 4C3 Number of ways of selecting 6 consonants from 12 and 3 vowels from 4 = 12C6 × 4C3 =(12!/((12-6)!*6!)) ×(4!/((4-3)!*4!)) =(12!/(6!*6!) ×(4!/(1!*4!)) =3696 It means we can have 3696 groups where...
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Number of ways to select 6 consonants from 12 = 12C6 Number of ways to select 3 vowels from 4 = 4C3 Number of ways of selecting 6 consonants from 12 and 3 vowels from 4 = 12C6 × 4C3 =(12!/((12-6)!*6!)) ×(4!/((4-3)!*4!)) =(12!/(6!*6!) ×(4!/(1!*4!)) =3696 It means we can have 3696 groups where each group contains total 9 letters (6 consonants and 3 vowels). Number of ways to arrange 9 letters among themselves =9! Hence, required number of ways =3696×9! read less
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12 c 6 * 4 c 3 * 9 !
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Maths Teacher

C(12,6)*C(4,3)*9!
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At present I'm working in sri krish international school, taking mathematics for 10th std

924 words can be formed
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Best Tuition in Tricity.

12C3 * 4C3
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**9*8*7*6*5*4*3*2*1
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**9*8*7*6*5*4*3*2*1
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