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(a) What is the total capacitance of the combination?
(b) Determine the charge on each capacitor if the combination is connected to a 100 V supply.
Asked by Kishore Last Modified
Answer 
Apoorva Purohit
(a) Capacitances of the given capacitors are
For the parallel combination of the capacitors, equivalent capacitor
is given by the algebraic sum,
Therefore, total capacitance of the combination is 9 pF.
(b) Supply voltage, V = 100 V
The voltage through all the three capacitors is same = V = 100 V
Charge on a capacitor of capacitance C and potential difference V is given by the relation,
q = VC … (i)
For C = 2 pF,
For C = 3 pF,
For C = 4 pF,
Navdeep Kalyan
Electrical Engineer With 2 Year Of Teaching Experience
If capacitors are in parallel they adds up.Do you know why?
In any electrical system if components are in 1.) series then current will be same throughout the elements ,2.) Parallel voltage will be same throughout the elements.
Now coming to second part of your question--please keep in mind that in capacitors Q=CV(where Q=charge),Now as described above voltage will be same in all three capacitors i.e same 100v is applied to 2pF,3pF nad 4pF.
Let say for 2pF--> here C=2pF,V=100,Q=?
=
Do this for rest of the capacitors.
Now why capacitor adds up in parallel
We know that
so
since Q=CV and {voltage is same}
Ceq=2+3+4=9pF
If the capacitors are connected in parallel, then the equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ + .......
Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pF
so, Ceq = C₁ + C₂ + C₃
Ceq = 2pF + 3pF + 4pF
= 9pF
(b) since the capacitors are in parallel, so the potential difference across each of them is same. e.g., V₁ = V₂ = V₃ = V = 100V
So, charge stored on capacitors are
Q₁ = C₁V = 2pF × 100V = 200pC
Q₂ = C₂V = 3pF × 100V = 300pC
Q₃ = C₃V = 4pF × 100 = 400pC
If the capacitors are connected in parallel then equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ + .......
Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pF
so, Ceq = C₁ + C₂ + C₃
Ceq = 2pF + 3pF + 4pF
= 9pF
(b) since the capacitors are in parallel, so the potential difference across each of them is same. e.g., V₁ = V₂ = V₃ = V = 100V
So, charge stored on capacitors are
Q₁ = C₁V = 2pF × 100V = 200pC
Q₂ = C₂V = 3pF × 100V = 300pC
Q₃ = C₃V = 4pF × 100 = 400pC
f the capacitors are connected in parallel, then the equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pF
so, Ceq = C₁ + C₂ + C₃
Ceq = 2pF + 3pF + 4pF= 9pF
b) since the capacitors are in parallel, so the potential difference across each of them is the same. e.g., V₁ = V₂ = V₃ = V = 100V So, charge stored on capacitors are
Q₁ = C₁V = 2pF × 100V = 200pC
Q₂ = C₂V = 3pF × 100V = 300pC
Q₃ = C₃V = 4pF × 100 = 400pC
View 4 more Answers
Related Questions
Two charges 5 × 10−8 C and −3 × 10−8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
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(b) After the supply was disconnected.
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